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9x^2-12x+4=64
We move all terms to the left:
9x^2-12x+4-(64)=0
We add all the numbers together, and all the variables
9x^2-12x-60=0
a = 9; b = -12; c = -60;
Δ = b2-4ac
Δ = -122-4·9·(-60)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-48}{2*9}=\frac{-36}{18} =-2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+48}{2*9}=\frac{60}{18} =3+1/3 $
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